We will show later in the text that if a projectile is fired from ground level with an initial speed of $v_{0}$ meters per second at an angle $\alpha$ with the horizontal, and if air resistance is neglected, then its position after $t$ seconds, relative to the coordinate system in the accompanying figure is
$$x=\left(v_{0} \cos \alpha\right) t, \quad y=\left(v_{0} \sin \alpha\right) t-\frac{1}{2} g t^{2}$$
where $g \approx 9.8 \mathrm{m} / \mathrm{s}^{2}$.
(a) By eliminating the parameter, show that the trajectory is a parabola.
(b) Sketch the trajectory if $\alpha=30^{\circ}$ and $v_{0}=1000 \mathrm{m} / \mathrm{s}$.
(GRAPH CAN'T COPY)