We will show later in the text that if a projectile is fired from ground level with an initial speed of $v_{0}$ meters per second at an angle $\alpha$ with the horizontal, and if air resistance is neglected, then its position after $t$ seconds, relative to the coordinate system in the accompanying figure on the next page is
$$
x=\left(v_{0} \cos \alpha\right) t, \quad y=\left(v_{0} \sin \alpha\right) t-\frac{1}{2} g t^{2}
$$
where $g \approx 9.8 \mathrm{~m} / \mathrm{s}^{2}$
(a) By eliminating the parameter, show that the trajectory lies on the graph of a quadratic polynomial.
(b) Use a graphing utility to sketch the trajectory if $\alpha=30^{\circ}$ and $v_{0}=1000 \mathrm{~m} / \mathrm{s}$.
(c) Using the trajectory in part (b), how high does the shell rise? $\quad$ (cant.).
(d) Using the trajectory in part (b), how far does the shell travel horizontally?