00:05
This question asks for the products of each of these reactions.
00:09
So starting with part a, we have an alkyne with h2 and palladium catalyst.
00:16
If we have an alkyne with this combination of reagents, then that will be reduced all the way to an alkan.
00:22
So our result will just be hexane.
00:26
And then in part b, we have that same alkyne with the lindlar catalyst.
00:31
So this will cause the alkyne to become an alkyne.
00:35
It won't go all the way to an alkan.
00:37
At that double bond.
00:38
And the linlar catalyst will add sin.
00:42
So we'll have a cis alkene here as our product.
00:49
In part c, we have sodium with liquid ammonia.
00:52
And again, the same alkyne.
00:54
So this is similar to the linlar catalyst because it will stop with the alken.
00:58
But instead of adding the hydrogen sin, it will add them anti.
01:03
So we will end up with a trans alken...