00:01
The magnitude of the x relation of a particle of charge q and mass m, charge q and mass m, moving in an electric field, e, is given by a is equal to q times e divided by m.
00:27
So we are given the magnitude of the electric field.
00:30
So magnitude of electric field e is equal to 33 kilo newton and 33 kilo newton is equal to 33 multiply by 10 to the power 3 newton.
00:51
Since one kilo is equal to 10 to the power 3 and then we have mass of proton.
00:58
So mass of proton is equal to 1 .67 multiplied by 10 to the power minus 27 kilogram.
01:11
This is mass of the proton and then charge of the proton qp and charge of the proton is 1 .67 multiply by 10 to the power minus 19 cologne.
01:27
Right and we need to find out the magnitude and direction of the proton's axelation now let's use this equation so x relation of the given charged particle is equal to q well q is 1 .67 multiplied by 10 to the power minus 19 multiplied by e field 33 multiplied by 10 to the power 3 divided by 1 .67 multiplied by 10 to the power minus 27 and therefore x relation a equals 3 .16 multiplied by 10 to the power 12 meter per second square.
02:34
Since the proton's charge is positive, the electric force on the proton, as well as its axolation, are directed in the same direction of the electric field...