00:01
So for this question, we are asked to find the two diasteremeres of the compound 2s4r 2 .4 octane dial.
00:08
And so for this question, we have to realize that we have two stereogenic centers, and therefore we are going to have two to the end stereosomers, or two to the two.
00:18
So we are going to have four stereogenic...
00:20
I'm sorry, four stereosomers.
00:24
So let me go ahead and write that down for us.
00:26
So we are going to have four stereosomers, including our...
00:31
R1 that we already have here, so our 2s4r.
00:38
So we can start by writing our 2s4r here.
00:43
And then in the previous question, we were actually asked to find the anantomir for this, and we found that it was the when the stereogenic centers were inverted.
00:52
So that would be our 2r 4s.
00:57
And so we can make a little quick note here and say that these two are anantomers.
01:10
And so that kind of leaves us with our other two stereo isomers that are going to be our diastereomers for this.
01:16
And so what we can go ahead and write them.
01:21
So that's going to be our 2r 4r and our 2s for s.
01:31
Right? and so we would say that these two are diastereomers and these two are diastomerers.
01:49
But we want to draw them out just so we can actually prove that this is the case.
01:54
So i'm not going to go and draw our an anemeteromers, but i'll go ahead and draw our diastereomers here, just to prove that they are, in fact, diastereomers.
02:03
And so what we have here is i'm going to go ahead and draw our 2s4r stereosomere, and what that's going to look like.
02:11
And so, right, of course, we're going to have our oh going away from us on both the 2 and 4.
02:21
Okay.
02:22
And so this is going to be our 2s4r...