00:01
So we have the following organic compound.
00:02
We have 2s4r, 2 .4 octane dial.
00:05
So we want to go ahead and draw the anantimer of this and figure out the stereochemical configuration of the anantimer.
00:12
So the first step here, of course, is that we want to draw our 2s4r -24 octane dial.
00:18
What is that going to look like? so we can go ahead and draw that out.
00:20
We're going to draw our octane parent chain.
00:24
It's going to look something like that.
00:26
And then we'll put an alcohol group in the 2 position with the s configuration.
00:32
So that'll be denoted by the dash.
00:35
And then in the four position, we want the r configuration, so that'll also be denoted by a dash.
00:40
If we were to assign priorities, we would see that.
00:43
And so we see that this position is going to be r.
00:47
This position is going to be s.
00:48
So here we do have our 2s4r 2 .2 octane dial.
00:52
And now we want to go ahead and draw the in antimere of that.
00:54
So how we would go about doing that is we have to remember that in antimers are mirror images of each other.
00:59
So we can draw a plaintiff's symmetry going down the middle here.
01:04
And now what we have to do is draw the mirror image of this, right? so we can just draw our parent chain again, the mirror image of our parent chain.
01:13
Right, so that's going to look like that.
01:18
And so we can draw the mirror image of our two position.
01:23
So that's going to be in the far back here.
01:25
That'll be there.
01:27
And then we can draw the mirror image of our alcohol in the fore position, and that's going to look like that.
01:33
And so now we want to figure out the sterechemical configuration of these alcohol groups...