Step 1: Write the equilibrium reaction for the dissociation of benzoic acid in water:
$$
\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}(\mathrm{aq}) \rightleftharpoons \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COO}^{-}(\mathrm{aq})+\mathrm{H}^{+}(\mathrm{aq})
$$
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