Question
What is the electric force on the chloride ion in the lower right hand corner in the diagram? since the ions are inwater, the "effective charge" on the chloride ions $\left(\mathrm{Cl}^{-}\right)$ is $-2 \times 10^{-21} \mathrm{C}$ and that of the sodium ions $\left(\mathrm{Na}^{+}\right)$ is $+2 \times 10^{-21} \mathrm{C} .$ The effective charge is a way to account for the partial shielding due to nearby water molecules. Assume that all four ions are coplanar.
Step 1
We can use Coulomb's law for this, which states that the force between two charges is given by $F = k \frac{q_1 q_2}{r^2}$, where $k$ is Coulomb's constant, $q_1$ and $q_2$ are the charges, and $r$ is the distance between them. Show more…
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What is the electric force on the chloride ion in the lower righthand corner in the diagram? Since the ions are in water, the "effective charge" on the chloride ions (Cl) is $-2 \times 10^{-21} \mathrm{C}$ and that of the sodium ions $\left(\mathrm{Na}^{+}\right)$ is $+2 \times 10^{-21} \mathrm{C}$. The effective charge is a way to account for the partial shielding due to nearby water molecules. Assume that all four ions are coplanar.
Salt crystal Four ions $\left(\mathrm{Na}^{+}, \mathrm{Cl}^{-}, \mathrm{Na}^{+}, \text { and } \mathrm{Cl}^{-}\right)$ in a row are each separated from their nearest neighbor by $3.0 \times 10^{-10} \mathrm{m} .$ The charge of a sodium ion is $+e$ and that of a chlorine ion is $-e$ . Determine the electric force exerted on the chlorine ion at the right end of the row due to the other three ions.
Salt crystal Four ions $\left(\mathrm{Na}^{+}, \mathrm{Cl}^{-}, \mathrm{Na}^{+},\right.$ and $\left.\mathrm{Cl}^{-}\right)$ in a row are each separated from their nearest neighbor by $3.0 \times 10^{-10} \mathrm{m} .$ The charge of a sodium ion is $+e$ and that of a chlorine ion is $-e .$ Determine the electric force exerted on the chlorine ion at the right end of the row due to the other three ions.
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