00:01
In this exercise, we have to find the ground state electronic configuration of the carbon that has an atomic number of 6.
00:06
And in question a, we have to write it in the spectroscopic notation.
00:13
Here, on the left, i have drawn the order according to which we should allocate atoms to, i'm sorry, allocate electrons to subshells in atoms.
00:27
So let's do it for the carbon.
00:28
First, we put two electrons in the 1s subshell, then two in the 2s subchel.
00:36
Notice that there are four electrons already placed, so we have only two to go.
00:44
The next sub -shell is the 3, i'm sorry, is the 2p, and 6 electrons can fit in the 2p sub -shell, but we only need 2.
01:00
So this here is the electronic configuration of the carbon.
01:06
In question b, we have to write the electronic configuration by explicitly writing the four quantum numbers.
01:16
Okay, so the four quantum numbers are n, l, so the principal quantum number is n, the orbital quantum number is l, the magnetic quantum number is ml, and the spin quantum number is ms.
01:33
So we have these four quantum numbers.
01:41
Okay.
01:42
And for the electron, the two electrons in the 1s shell, n is one, that's the principal quantum number, l can only be zero, okay, because the s shell has an angular, angular momentum of zero.
02:00
Ml can also only be zero because ml can range from minus l to l, but l...