00:01
I chose the test charge q to be the orange of the coordinate system.
00:06
And firstly, we can calculate the electric force exerted by q1 and q2 on test charge q.
00:18
So we can calculate the magnitude of f1 and f2 because the source charge have the same magnitude, of 2 nanokuna, so the magnitude of their electric force should have the same magnitude 2.
00:40
So it's q positive times q over the square of their distance.
00:47
And we plug in the numbers, we'll get its 0 .72 times 10 to negative 5 newtons.
00:56
And the direction of the f1 and f2 both point away from the source charge, so f1, point in this direction.
01:12
And f2 exerted by q2 point in this direction.
01:19
And we can add f1 and f2 together.
01:24
As we can see, the x component, the f2x, should cancel out the f2y because they point in opposite directions.
01:40
And f1y should equal to f2y...