00:01
This question is asking us to find the formula name for a hydrate that is 85 .3 % barium chloride and 14 .7 % water.
00:11
So let's start by finding the formula for each of these.
00:14
For barium chloride, we know there is going to be barium and there's going to be chlorine.
00:22
On its own, barium has a charge of plus two and chlorine has a charge of minus one.
00:30
So in order for this compound to have a total charge of zero, there have to be two chlorine.
00:36
For every barium.
00:39
For water, i hope we all know the formula is h2o, two hydrogens for every oxygen.
00:50
In order to find the formula, we're going to need the ratio of barium chloride to water in terms of moles.
00:58
And so we're going to eventually need to use the molar mass.
01:01
So let's write those down in the hoopla.
01:04
In order to find the molar mass of a compound with multiple atoms, we need to add the molar masses of you of the individual items which can be found on a periodic table.
01:16
So for barium chloride, adding the molar mass of thorium with twice the molar mass of chlorine gives us 208 .28 0 .28 grams per mole.
01:37
And for water, adding twice the lull mass of hydrogen plus the molar mass of oxygen, that gives us 18 .02 grams per mole.
01:54
All right.
01:56
So now we have these percentages that we need to get into grams in order to get moles.
02:03
So we can assume that the hydrate has any number of grams.
02:08
It's easiest to assume 100 grams so that we can keep these numbers as the number of grams for each of the individual compounds within the hydrate.
02:17
So for example, for barium chloride, we have 85 .3 grams.
02:26
And for water we have 14 .7 grams.
02:51
So now that we have grams, we can easily use the molar mass to get the number of moles of each of these.
02:56
So for barium chloride, we can divide by the molar mass, which is the same as multiplying by the reciprocal of the molar mass...