00:01
In this exercise, we have to calculate what is the maximum number of electrons in the n equals 5 shell.
00:10
So basically, for a given principal quantum number n, remember that l, the orbital quantum number, can range from 0 to n minus 1.
00:21
So in our case, it can be 0, 1, 2, 3, and 4.
00:27
And remember that for a given l, the possible values of the magnetic quantum number m that vary from minus l to l in steps of 1.
00:44
And for each magnetic quantum number, we have two possible values for the spin quantum number, plus or minus one half.
00:53
Okay, so let's start with the l equals 0 subshell.
01:02
In that case, m can only be 0, and ms can be plus or minus 1 half, so there are two possible states in this case.
01:14
Then we have l equals 0, i'm sorry, l equals 1, m can be minus 1, 0 or 1, and for each 1 value of m ms can be plus or minus one half so notice that there are three possible values of m and for each value of m there are two possible values of ms so in total there are two times three states six states for l equals two the possible values of m are minus two minus one zero one and two notice that there are five values of m ms as always can be plus or minus one half so so in total, there are 5 times 2 possible states, which is 10.
02:08
Therefore, l equals 3.
02:12
M can range from minus 3 to positive 3.
02:18
In total, there are 7 possible values of m...