Question
What is the measure of one of the larger angles of the parallelogram that has vertices at $(-2,-2),$ $(0,1),(5,1),$ and $(3,-2) ?$(A) $117.2^{\circ}$(B) $123.7^{\circ}$(C) $124.9^{\circ}$(D) $125.3^{\circ}$(E) $131.0^{\circ}$
Step 1
We can do this by subtracting the coordinates of the vertices: Vector $\overrightarrow{AB} = (0 - (-2), 1 - (-2)) = (2, 3)$ Vector $\overrightarrow{BC} = (5 - 0, 1 - 1) = (5, 0)$ Now, we can find the angle between these two vectors using the dot product Show more…
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