00:01
In this exercise, we have to calculate what's the minimum energy of a photon in order for you to be absorbed by a hydrogen atom.
00:09
And we have to suppose that the hydrogen atom is that it's ground state, so n -initial equals 1.
00:17
And let's calculate it.
00:20
First of all, let's remember that the energy of the nth level of the hydrogen atom is given by minus e -0 over n -square.
00:29
And here is zero is the energy, the magnitude of the energy of the ground state.
00:37
So it's what i'm calling 13 .6 elective volts.
00:46
And we're going to calculate what is the energy of a photon.
00:50
So if a photon is absorbed by the hydrogen atom, its energy is going to be equal to the final energy of the hydrogen atom, so e and f.
01:08
Nf is the final energy level of the hydrogen atom minus the initial energy of the hydrogen atom.
01:24
So, substituting the equation for e -n here, we're going to have e -0 over and over, sorry, not over anything, e0 1 over n i squared minus 1 over n f squared and we know that for our case here n i i i'm going to just right here that e0 is 13 .6 and we know that n i the initial energy level of the hydrogen atom is 1 and the final energy level is to be determined okay and we want to know what's the smallest energy of the photon delta e? well, the smallest energy will happen when we have the smallest number of nf...