00:01
Here we have to find the mass of each of the given solutes.
00:03
For solution a, we have 2 .50 liters of 13 .1 molar hydrochloric acid.
00:10
So we're going to start by writing 13 .1, but we're going to change that molarity to moles per one liter.
00:18
Then we're going to multiply by 2 .50 liters.
00:22
Here those liters cancel out, you are left with just moles of hydrochloric acid.
00:28
So next we're going to say one mole of hydrochloric acid weighs 36 .458 grams.
00:37
So that is the molecular weight of hydrochloric acid.
00:42
So we have 13 .1 times 2 .50 times 36 .458.
00:49
So this comes out to be 1193 .9995 grams.
00:56
Let's put this in a reasonable number of sig figs.
00:58
We'll just say 1194 grams of hcl.
01:05
Now for number two, the first thing we have to do is convert those milliliters to liters.
01:10
So that will become 0 .0156 liters.
01:14
Now we can use the same formula as above.
01:17
We start with the big m, two moles per one liter, multiply by the number of liters, and then multiply by the molar mass for sodium hydroxide.
01:31
So one mole of sodium hydroxide, that weighs 39 .998 grams...