What product would you expect from reaction of cyclohexene with HBr? With HCl? (EQUATION CAN'T C

What product would you expect from reaction of cyclohexene...

Key Concepts

Nucleophilic Attack

Following the formation of the carbocation intermediate in an electrophilic addition reaction, the halide ion, acting as a nucleophile, attacks the positively charged carbon. This final step completes the addition process by forming a new carbon-halogen bond, resulting in the formation of a haloalkane product.

Electrophilic Addition Mechanism

This concept describes how alkenes, which contain a carbon–carbon double bond, react with electrophiles such as hydrogen halides. In such reactions, the electron-rich double bond attacks the electrophilic hydrogen, leading to the formation of a carbocation intermediate that is subsequently attacked by a nucleophilic halide ion, resulting in the addition of the halide across the double bond.

Markovnikov’s Rule

Markovnikov’s rule is a guiding principle for predicting the regioselectivity of electrophilic addition reactions to alkenes. It states that in the addition of HX to an unsymmetrical alkene, the hydrogen atom attaches to the carbon with more hydrogen substituents, while the halide binds to the carbon with more alkyl substituents, thereby forming the more stable carbocation intermediate.

Transcript

00:02 So in this question, we're asked to determine the product that would form from the reaction between cyclohexene and hydrogen hbr or hcl.

00:12 So the way that this reaction would work is it's actually a markovnikov addition reaction.

00:21 So the way that it would work is originally you would be left where you have a cyclohexene and you have a hydrogen non -disc bromine.

00:32 So a double bond is a very good nucleophile because it has an excess of electrons.

00:40 So it's going to grab the hydrogen.

00:42 And when it does that, the hydrogen is going to leave.

00:46 And so it's going to give its electrons to brony.

00:48 So now there's going to be a bond between.

00:52 So an addition reaction has taken place because the double bond is going to be removed.

00:57 And then say the hydrogen comes over here.

00:59 In this case, it doesn't matter where the hydrogen goes because the molecule is equal.

01:06 But if there was a molecule here, say like there was an additional like methyl group over here or something like that, then it would matter because the hydrogen would go on the side where there are less molecules so that the bromine would go on the side where there are more molecules.

01:22 But that does not apply in this case.

01:24 So hydrogen would go here.

01:26 But since the double bond has been removed, this is going to leave this carbon as positively charged.

01:32 And the reason why is because originally the carbon was in a double bond...

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