Question
What spectral transition(s) gives rise to the blue color of cobalt glass? Why are octahedral $\mathrm{Co}$ (III) complexes usually not blue, in contrast with tetrahedral $\mathrm{Co}$ (II) complexes?
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Cobalt can exist in multiple oxidation states, but in this case, we are focusing on cobalt (II) and cobalt (III). Cobalt (II) is in the +2 oxidation state, while cobalt (III) is in the +3 oxidation state. Show more…
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You are studying an octahedral transition metal complex that contains the $\mathrm{Co}^{2+}$ ion and discover that it has a strong absorption in the blue region of the visible spectrum. Would you suspect (not conclude) that this complex is high spin or low spin. Explain?
Very few simple salts of cobalt(III) exist Why? The known complexes, for example CoF3, are unstable and readily decompose to species in which cobalt exists in the more favourable +2 oxidation state. This oxidation state is stabilised as [Co(H2O)6]2+ in aqueous solution. The coordinated water molecules are substituted by ammonia molecules and the +3 state of cobalt becomes more favourable. Indeed, [Co(NH3)6]2+ is unstable in the presence of moisture and oxygen. The product of the reaction between [Co(H2O)6]2+, hydrogen peroxide, ammonia and hydrochloric acid contains Co(III), and is given the formula CoCl3.5NH3 by analogy with hydrated cobalt(II) chloride which is formulated as CoCl2.6H2O in the solid. CoCl3.5NH3 is probably the oldest coordination complex known {Cr(II) systems?}. The 1913 Nobel Prize for Chemistry was won by Alfred Werner for assigning the correct structure to CoCl3.5NH3 and similar compounds. In this experiment, some of Werner's work will be repeated and so more correctly identify the composition of CoCl3.5NH3. Refer to the Inorganic lectures, notes and Inorganic text books for extra reading!
Solutions of $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+},\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}($ both octahedral $)$ and $\left[\mathrm{CoCl}_{4}\right]^{2-}$ (tetrahedral) are colored. One is pink, one is blue, and one is yellow. Based on the spectrochemical series and remembering that the energy splitting in tetrahedral complexes is normally much less that that in octahedral ones, assign a color to each complex.
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