00:01
So we need to draw the structure, convert it to a newman projection, and then rotate the group so that the h and the hydrogen and the bromine to be eliminated have an anti -peripliner or a staggered relationship.
00:16
So let's draw this out.
00:18
So we have a methyl attached to a carbon, carbon, carbon, and methyl.
00:28
And then we have a methyl, hydrogen, hydrogens, then hydrogen and a bromine.
00:45
So to draw the newman projection for this, it would be bromine, hydrogen, a methyl.
00:58
That means there's a metal here, the ch2, ch3, and then the hydrogen here...