00:01
So we have the following alkaliad, and we want to know what would happen if we performed e2 elimination on it.
00:06
Well, remember that when performing e2 elimination, that we want the reacting hydrogen and leaving bromine to be anti -parapaliner from each other.
00:14
But in this case, they are not.
00:16
And so what we can do is we can rotate, in this case, carbon number one by 120 degrees in order to make sure that they are anti -parriplanner to each other.
00:25
So when we do that, the resulting bondline structure will look something like this.
00:29
So we'll go ahead and rotate carbon number one by 120 degrees clockwise.
00:45
And so that will look something like this.
00:50
Methad group is going away from us now.
00:56
The bromine is coming towards us.
00:58
And the hydrogen is in the plane of the organic compound.
01:03
And for carbon number two, everything will remain the same.
01:07
So we'll still have the methyl group coming towards us and we'll have the hydrogen going away from us.
01:13
And now we see that they exhibit anti -parapraplanar geometry.
01:19
So now we can perform our e2 elimination...