00:01
For the chlorination of propane, the two isomers shown here are possible, so the primary halogen alkan or a secondary halogenalcane.
00:09
So propane has six hydrogen atoms on terminal carbon atoms, called primary hydrogen atoms, and then two of them on the interior carbon atom called secondary hydrogen atoms.
00:21
If the two different types of hydrogen atoms were equally reactive, what ratio of one chloropropine to two chloropropine would we expect as monochlorination products? so in our propane molecule, i have one, two, three, four, five, six, six primary hydrogens.
00:43
If one of those hydrogens reacts and is substituted with a chlorine atom, you'll get this first isomer.
00:52
So i have six for the primary hydrogens.
00:59
I have two hydrogens in the middle, and if either of those are replaced with chlorine, you'll wind up with the secondary.
01:06
Compound.
01:08
So secondary compound, you'd have two of those things.
01:11
So it's a six to two ratio.
01:14
And if you simplify that, you get that it is a three to one relationship.
01:20
So you would get from this to this, for primary versus secondary, it's a three to one ratio for those monoclorination products.
01:29
Now the result of a reaction yields 55 % to chloropropine and 45 % one chloropropine...