00:01
Okay, let's start by writing a balanced equation for what's happening here.
00:06
Okay, and the nitric acid is reacting with strontium hydroxide in a 2 -1 ratio to make two water molecules and strontium nitrate.
00:23
So they've given us some information about our strontium hydroxide.
00:28
So let's go ahead and calculate our moles of sr -o -h -2.
00:34
We'll just do that by multiplying the molarity times the liters, so 0 .21.
00:38
1 .8 molar.
00:41
Multiply that by 0 .0584 liters.
00:49
So that'll give us our moles.
00:53
0127 moles.
00:57
And we'll do a mole ratio here to get over to our nitric acid.
01:01
So we're changing moles of strontium hydroxide to moles of nitric acid, which is 2 to 1.
01:14
So we'll get 0 .0255 .000.
01:17
Moles of our nitric acid.
01:22
And we know the volume.
01:24
So we're going to divide by the volume here in liters.
01:30
So we're going to get that we have 1 .02 molar, hn .03.
01:37
Since that's a strong acid, we know that the concentration of h plus will also be 1 .02 molar.
01:47
So then minus the log of that will give us the ph.
01:51
And that'll be negative 0 .3.
01:54
0 .0796.
01:58
Okay.
02:05
Okay...