Question
When 3-methyl-1-butene reacts with HBr, two alkyl halides are formed: 2-bromo-3-methylbutane and 2-bromo-2-methylbutane. Propose a mechanism that explains the formation of these products.
Step 1
The Ļ electrons of the double bond attack the hydrogen atom of HBr, resulting in the formation of a carbocation. This step generates a bromide ion (Brā») and a carbocation intermediate. The double bond is between the first and second carbon atoms, so the proton can Show more…
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