Question
When 3-methyl-1-butene reacts with HBr, two alkyl halides are formed: 2-bromo-3-methylbutane and 2-bromo-2-methylbutane. Propose a mechanism that explains the formation of these two products.
Step 1
This is represented by the following equation: \[ \text{CH}_3\text{CH}= \text{CHCH}_3 + \text{HBr} \rightarrow \text{CH}_3\text{CH}_2^+ + \text{Br}^- \] Show more…
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