00:03
This is the answer to chapter 15, problem number 59, from the smith organic chemistry textbook.
00:11
And this problem says, when 3 -3 -dymethyl -1 butene is treated with hbr alone, the major product is 2 -bromo -2 -3 -dymethylbutane.
00:21
When the same alkene is treated with hbr and peroxide, the sole product is 1 -bromo -3 -dymethylbutane.
00:28
Explain these results by referring to the mechanisms.
00:31
Okay, so let's do that.
00:36
So the molecule that we're talking about, 3 -3 -dymethyl 1 -butene looks like this.
00:55
There we go.
00:56
So 3 -3 -dymethyl 1 -butene.
00:59
And so when we treat this with hbr under non -radical conditions, the mechanism is going to be this.
01:10
So the electrons of the double bond will grab this proton.
01:17
The hbr bond breaks.
01:20
And so we have this after the first step with a carbocadion located here on this secondary carbon.
01:35
And what's going to happen here is we will get a 1 -2 methyl shift.
01:49
So a 1 -2 methyl shift to get this intermediate.
01:59
And so now our carbocation is on a tertiary carbon.
02:06
And so actually, i guess, not that it matters since the molecule is symmetrical, but it would be more correct to say that the carbocation is located here.
02:18
Again, it doesn't matter the molecule symmetrical.
02:23
And so now we have a tertiary carbocadion.
02:26
And so now the bromine ion, the bromide, that we formed in our first step of this mechanism can come and attack and add there.
02:43
And so we get to our product, which is this.
02:54
Okay, so 2 -bromo -2 -3 dimethylbutane.
03:01
Okay...