Question
When 3-methyl-2-butanol reacts with HBr, the expected product is 2-bromo-3-methyl-butane. But the actual product formed is 2 -bromo-2-methylbutane. Account for this.
Step 1
It looks like this: \[ \begin{array}{cccccccc} & & & CH_{3} & & & & \\ & & / & | & \backslash & & & \\ H_{3}C - CH - CH - CH_{2} - OH & & & & & & & \\ & & \backslash & | & / & & & \\ & & & CH_{3} & & & & \\ \end{array} \] Show more…
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Reaction of 3-methyl-2-butanol with HBr yields two products. One is the regular product of SN1 (2-bromo-3-methylbutane minor product) and second (major) is the product of rearrangement. Write mechanism for the formation of this major product.
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