00:01
In this question, you have a battery that is connected to a 100 oom resistor.
00:09
And when that happens, the current is found to be 4 .0 ampias.
00:16
The battery has internal resistant r, small r.
00:21
And then when the battery is connected to a 400 oom resistor, the current is 1 .01 ampere.
00:40
So we want to find the emf and the internal resistance of the battery.
00:46
So to do this question, you'll be using the equation that type b equals to emf minus ir.
00:57
Okay.
01:00
So let's say this is circuit one, this is circuit two.
01:07
Okay, so for circuit one, we have a circuit one.
01:16
Delta b which is ir i times big r which is 400 which is and then it's equal to the mf minus 4 times r okay so the equation is 400 equals to e minus 4r so this is our first equation and then for circuit 2 we have have delta v equals to i2 r2 which is 1 .01 times 400 and we get 404 both and this is equal to e minus 1 .01r okay so the second equation is 404 is equal to e minus 1 .01r okay so the second equation is 404 is equal to emf minus 1 .01r so we have two equations and then we can do this 2 minus 1...