When an MOS transistor is biased with $V_{D}>V_{D}$ (sat.), the effective channel length is reduced by $\Delta L$ and the current $I_{D}^{\prime}$ is larger than $I_{D}$ (sat.), as shown in Fig.6-32. Assuming that the depleted region $\Delta L$ is described by an expression similar to Eq. $(6-30)$ with $V_{D}-V_{D}($ sat. $)$ for the voltage across $\Delta L$, show that the conductance beyond saturation is
$$
g_{D}^{\prime}=\frac{\partial I_{D}^{\prime}}{\partial V_{D}}=I_{D} \text { (sat.) } \frac{\partial}{\partial V_{D}}\left(\frac{L}{L-\Delta L}\right)
$$
and find the expression for $g_{D}^{\prime}$ in terms of $V_{D}$.