Question
When fumarate reacts with $\mathrm{D}_{2} \mathrm{O}$ in the presence of the enzyme fumarase, only one isomer of the product is formed, as shown here. Is the enzyme catalyzing a syn or an anti addition of $\mathrm{D}_{2} \mathrm{O} ?$
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Fumarate is a trans isomer, which means that the two carboxyl groups are on opposite sides of the molecule. Show more…
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When fumarate reacts with $\mathrm{D}_{2} \mathrm{O}$ in the presence of the enzyme fumarase, only one isomer of the product is formed. Its structure is shown. Is the enzyme catalyzing a syn or an anti addition of $\mathrm{D}_{2} \mathrm{O} ?$
The rate of an enzyme-catalyzed reaction can be slowed down by the presence of an inhibitor (I) that reacts with the enzyme in a rapid equilibrium process. $$\mathrm{E}+\mathrm{I} \rightleftharpoons \mathrm{EI}$$ By adding this step to the mechanism for enzyme catalysis on page 641, determine the effect of adding the concentration $\left[\mathrm{I}_{0}\right]$ on the rate of an enzyme-catalyzed reaction.
The graph below shows two curves obtained from an enzyme reaction, either in the presence or absence of substance X. Substance X is: with X without X [S] 1. an activator of the enzyme and lowers Km. 2. an activator of the enzyme and raises Km. 3. X is an inhibitor of the enzyme and raises Km and lowers Vmax. 4. an inhibitor of the enzyme and lowers Km. 5. an activator of the enzyme and lowers Km and raises Vmax.
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