00:01
This question looks like a lot of math, but it all makes sense if you walk through it slowly.
00:07
So we're going to start off with your equation.
00:10
C .a.
00:11
C .o .3 equals caco plus co2.
00:14
We're trying to see when we're at maximum of caco3, how much co2 are we using how much is left.
00:22
So we start off with the value given, which is 2 .38 kilograms of caco3.
00:28
And to convert from kilograms to grams, so we multiplied by 100 kilograms, grams cross out.
00:35
So now we have grams.
00:38
Next we want to take our value from grams to moles.
00:43
So if you look up how much one mole is, it is for ca -co3, it's a hundred point zero nine grams.
00:48
So grams here cross out and now we're in most of co3.
00:54
But we don't care about the moles of ca co3, we want to know about co2...