00:01
In this problem, we need to balance the equation for the reaction between copper and nitric asset, which produces copper to nitrate, nitrogen dioxide, and water.
00:37
Okay? so the best way to balance this reaction is using the redox balancing method.
00:47
Okay, the real equation balancing method.
00:52
Why? because you immediately realize that copper transitions from an oxidation state of zero to an oxidation state of positive two.
01:05
So that would be our first half reaction, the oxidation of copper, from copper zero to copper positive two, which is the ion here.
01:22
Now we balance the charges.
01:25
We have two electrons here.
01:28
Zero net charge on the reactant.
01:30
Zero net charge net charge.
01:32
Now a reduction, a reduction, half reaction, which is the reduction of nitrate.
01:45
And you're going to find nitrate on this side, two nitrates here, and then nitrogen dioxide.
01:58
So we have nitrate getting converted to nitrate itself.
02:06
So some nitrate does not change and some nitrate is reduced to nitrogen dioxide.
02:16
Okay, so first let's balance the nitrogen.
02:21
We have two nitrogen's here and only one here.
02:26
So we place a two here.
02:27
No, sorry, we have two nitrogens here.
02:29
Plus one, three nitrogen.
02:33
So we place a three, equation of three here.
02:37
Now, this is a reaction that takes place in an acidic environment given by nitric acid.
02:44
Therefore, we balance oxygens and hydrogens with water and hydrogen ions.
02:52
Okay, so let's first balance oxygens.
02:56
We have nine oxygens on the reactant and then six plus two, eight oxygens on the product.
03:07
So we need a molecule of water here to balance oxygen...