Question
Write a balanced equation for the reaction of a copper penny in a dilute nitric acid solution.$$\mathrm{Cu}(s)+\mathrm{NO}_{3}^{-}(a q) \longrightarrow \mathrm{Cu}^{2+}(a q)+\mathrm{NO}(g)$$
Step 1
One half reaction will be the copper solid going to the copper two plus. The second half reaction will be the nitrate ion going to the nitrogen monoxide. The half reactions are: \[ \mathrm{Cu}(s) \rightarrow \mathrm{Cu}^{2+}(a q)+2 Show more…
Show all steps
Your feedback will help us improve your experience
David Collins and 78 other Chemistry 102 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Silver metal reacts with nitric acid to give silver ion and nitric oxide. Write the balanced equation for this reaction.
When solid copper is added to nitric acid, copper(II) nitrate, nitrogen dioxide, and water are produced. Write the balanced chemical equation for the reaction. List six mole ratios for the reaction.
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD