Question
When the current in the portion of the circuit shown in Figure P32.59 is 2.00 A and increases at a rate of0.500 $\mathrm{A} / \mathrm{s}$ , the measured voltage is $\Delta V_{a b}=9.00 \mathrm{V}$ . When the current is 2.00 A and decreases at the rate of $0.500 \mathrm{A} / \mathrm{s},$ the measured voltage is $\Delta V_{a b}=5.00 \mathrm{V} .$ Calculate the values of (a) $L$ and (b) $R$
Step 1
This can be rearranged to give $\varepsilon = IR + L \frac{dI}{dt}$, where $\varepsilon$ is the electromotive force, $I$ is the current, $R$ is the resistance, and $L$ is the inductance. Show more…
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When the current in the portion of the circuit shown in Figure $\mathrm{P} 32.54$ is 2.00 $\mathrm{A}$ and increases at a rate of 0.500 $\mathrm{A} / \mathrm{s}$ , the measured potential difference is $\Delta V_{a b}=9.00 \mathrm{V}$ . When the current is 2.00 $\mathrm{A}$ and decreases at the rate of $0.500 \mathrm{A} / \mathrm{s},$ the measured potential difference is $\Delta V_{a b}=$ $5.00 \mathrm{V} .$ Calculate the values of $L$ and $R$
For the circuit shown in Figure P 18.20, calculate (a) the current in the $2.00-\Omega$ resistor and (b) the potential difference between points $a$ and $b, \Delta V=V_{b}-V_{a}.$
For the $R L$ circuit shown in Figure $\mathrm{P} 32.17$ , let the inductance be 3.00 $\mathrm{H}$ , the resistance $8.00 \Omega,$ and the battery emf 36.0 $\mathrm{V}$ . (a) Calculate the ratio of the potential difference across the resistor to that across the inductor when the current is 2.00 $\mathrm{A}$ . (b) Calculate the voltage across the inductor when the current is 4.50 $\mathrm{A}$ .
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