00:01
Okay, so we want to determine the following are cis or trans isomers.
00:04
And the first one, we have two, three, die methyl two butene.
00:06
So, butene is four carbons, the ein and positive of an achine, and it's on carbon two.
00:12
And we have a methyl group on carbon two and three, which is a ch3.
00:21
So we have this structure.
00:23
And the cis and trans isomers exist.
00:25
If each carbon of the achine has two non -identical groups, so because we have two methyl groups on the same carbon, this would not be a cis or transomers.
00:35
Transylosomer.
00:38
And then for b, we have 2 chloro2 butine.
00:49
So this would be a cyst and translysmir because this carbon has a methyl group in a chlorine.
00:54
And this one has a methyl and a hydrogen.
00:58
So we can put the chlorine up here.
01:02
And it has more priority over the methyl group because it has a higher top number...