00:01
In this question we've been asked to conclude which of these compounds exist as a cis trans isoma and we've been asked to draw them.
00:09
So looking at the first one, we've got two, three, dimetal, two, butin.
00:16
So looking at this, we've got two methyl groups and we have a double bond.
00:27
Looking at this, we cannot have, if we are to number this, one, two, three, four.
00:33
Looking at this, the carbon atoms are attached to identical methyl ch3 groups.
00:44
So the compound does not show geometric isomerism.
00:48
Therefore, it cannot exist as a cis -potransisomer...