00:01
We want to determine whether the sequence a .n is equal to the square root of n times sign of one of the square root of n converges or diverges, and if it converges, what it converges to.
00:13
So first notice, if we were to just look at this as n goes to infinity, well, the square root of n goes to infinity.
00:25
One over the square root of n will go to zero, and then sine of zero is zero.
00:31
So i don't know what infinity times 0 is supposed to mean.
00:35
It's one of our indeterminate forms.
00:37
But you might notice if we rewrite this as sine of 1 over the square root of n, divided by 1 over the square root of n.
00:47
Now, the numerator goes to 0 and the denominator goes to 0.
00:54
So this implies we can use lopatols.
01:00
So we have the limit as an approaches infinity is equal to by lopithol's...