00:01
Okay, so problem number 30 in chapter 19 asks to write a balanced equation describing the reaction of aluminum metal with concentrated aqueous sodium hydroxide.
00:14
So do this reaction, we have aluminum metal, so that's a solid phase.
00:24
And then we have sodium hydroxide concentrated, and this is aqueous.
00:30
So looking at the setup for this reaction, we can see that this is going to be a simple, single displacement reaction.
00:46
So we're going to have the na replace, i mean, the aluminum is going to replace the sodium here.
00:57
So al is going to go with that.
01:00
So what we're going to have here for our actions is aloh.
01:11
But we know that al is 3 plus and oh is 1 minus.
01:19
So that means we're going to have to have three ohs.
01:29
So we have al, oh3.
01:32
And then while our sodium is still left over, so what happens is our sodium is just going to be displaced.
01:44
And that's to keep the balance of the reaction.
01:48
So as for the phases of these two things, if they look at the solubility chart, you will see that.
01:57
If you look at a solubility chart, you'll find out that this is indeed a solid still.
02:03
And then na is on its own...
