write-a-matrix-equation-that-determines-the-loop-currents-m-if-matlab-or-another-matrix-program-is-2

Name: write a matrix equation that determines the loop currents m if matlab or another matrix program is 2
Uploaded: 2020-07-17
Duration: 2 min 27 s
Channel: Numerade
Description: Write a matrix equation that determines the loop currents. [M] If MATLAB or another matrix program is available, solve the system for the loop currents.

Question

Write a matrix equation that determines the loop currents. [M] If MATLAB or another matrix program is available, solve the system for the loop currents.

Jack Chen · Accepted Answer

Okay, So in this proper and face on the cardinal formula, um, we know that the voltage you closed to the total current I turns on the total resistance in each group. So based on this equation, we can ride out for difference for different equations for each loop. So for the first look, we have six I one miners. I ju equals toe 30. Um, this for the second group, we have miners, I want plus nine times I to minors. For I three equals to 20. The third loop is minors. For I to a class seven I three miners two times I four equals to 40. And for the last hope, we have minus 203 plus seven. High four equals to 40. And we can turn worth this system of equations into the into a matrix form. I just collect this coefficient in front, off each variable I want try for and put them in a metrics. And then times are column vector. So I want I chew. I&#x27;ve read in 94 he closed to the wattage in each look. And, uh, once we once we write out this metrics, we can use the calculator. Teoh, get the solution to this system off equations, and I just direct you write it out. Okay, so this is the solution to this equation.

Jack Chen · Answer

it is. So in this program we use the cooking off equation the water gee, close to the total current tons. Total resistance in each Duke clear. So, by this formula for the first rope, we have 12 I one miners, seven I to minors four times I forward close to 40. Well, a second look, minds seven i one plus 15 to minus six. I three equals the federal minus six I to plus 14 high three miners five by four because to 20 for the last loop, minus 41 plus 13 high for minors. Five i three cost minus to be careful about the last loop because you can see that&#x27;s the direction off that battery. Um, it&#x27;s different with the direction of the current. So, um, either we put a negative sign here or put a negative Saiful off this left inside part. So by this construction, we can ride out its magics from just collect off its Corey visions, and you can see that this convention metrics is actually symmetric and multiply this nature expired column vector because to the wattage we can use, um, we can use the software or calculator to solve this to self this system of equations by are using these metrics form. So we have I have the following result. I want, of course, believe in times 43. So this is the solution to this our system of equations.

Jack Chen · Answer

okay in this program where? Use the curtain off formula. What age? Because to the total current times your total resistance. Um, so we have five different lobes in a way that means we have five different immune equations. So for the first GOP at NYU, I want minus eyes. I tu minus. I fall minus four times I five because 2 50 the second group minus. I want cross seven. I tu minus twice off I three minus three. I five equals to 30 so he should be minus 30. So be careful about this. On the direction of the ah batteries, I eyes different with the direction of current. That means we have a miner&#x27;s in front off this wattage for the third group minus two. I two pass tonight three minus three. High four minus three. I five equals to 20. The next group we&#x27;ll be miners. I want minus three. I three process seven I four miners 25 because to minus 40. So there&#x27;s another 90. If sign here for the same reason. And for the last hope, we don&#x27;t have any pottage. That means the total body gee, close to zero, and we can convert this system of equations into matrix form by collecting off its coefficient. Yes, we have. No, I minus 10 minus 14 So I can see that this coefficient metrics is, in fact symmetric, not deprived by, um, the variables. I want to high five. You closed to the wattage, and we can use, um calculator to figure out on the solution. Justin, put this matrix into the calculator. We have I one equals 24 0.0 to a close to minus 4.38 Hi. Three close to minus 2.90 I fall. He caused to a minus 5.0. And I five equals two miners. Your point. Nice six. So this is a solution to this. It&#x27;s not be prisons.

Jingyun Wang · Answer

the question asked to find a solution off the system. First, we need to change a system off equation into a semantic my tricks for remember, we need to find the reduce rational form to find the answer. We want this position to be one so we can apply the identity. Horrendous ease A plus B times parentheses a minus bi equal a square minus B square. We have imaginary number here, so we need to remember I equal square root off negative one. I tell us I equal negative one, So parentheses. One plus I times parentheses one minus I you cool? One square minus. I square equal one by this negative one equal to so for row one, we can do one minus I over to time is a real one. Copy wrote to furrow to we can do parentheses. Nega one First I How&#x27;s the roll? One my s a road to coffee row one Every time when we see all zero seeing Vairo, which means there&#x27;s a favorable for this case. Acts two is a free variable and this is the reduced role Rational form so we can get acts. Two can be any number X one equal one plus three I over to times x two. This is your final answer

Thomas Emment · Answer

Okay. We want to write a systems equation at a matrix equation on what we have to do. You hear? If you have to find the consummate tricks the variable matrix on the coefficient matrix on, then write them out. And I absolutely think that makes sense. Okay, so we start for the coefficient matrix here. Now, the coefficients, a lot of numbers in front variables with a three one, a five and a one on DSO. See, our first road here is corresponding to our acre. Efficient on our second row here is corresponding to our beacon. Efficient. So far, variable matrix. Since when we timed this out, it&#x27;ll be wth the road times. This column here. Well, not first value to be a because we want the first thing to be times by now. I was like to be on this is our variable matrix on. Then finally, we just need our matrix of Constance, which is just gonna be our answers. Output here zero into. And this is our question of matrix. Thank you.

Jingyun Wang · Answer

the question asked to find a solution off the system. First. Winning true changer given system into augmented grammar trips for Remember, we need to find the reducer or rational form to find the answer. We want this position to be one so we can apply the identity. Parentheses. A plus B parentheses. A minus bi equal a square minus B square. We have imaginary number here, so we need to remember I equal square Ruoff Negative one i times I equal Negative one. So here we can do parentheses one plus i times parentheses one minus I you cool One square minus. I square equal one minus degree one you call chew. So for one, we can do one. Plus I over to comes Rule one copy Row two Furrow to We can do parentheses one plus I times Rule one. My eyes wrote you corporal one Every time when we see all zeros in one row, which means there&#x27;s a favorable for this case acts two is there favorable. This is the reduce a rational form so we can get axe to can be any number x one equal parentheses, one minus. I times acts to, and this is your final answer

Problem

Write a matrix equation that determines the loop …

Problem 6 Easy Difficulty

Write a matrix equation that determines the loop currents. [M] If MATLAB or another matrix program is available, solve the system for the loop currents.

Answer

(b) $\left[\begin{array}{c}{6.36} \\ {8.14} \\ {11.73} \\ {4.78}\end{array}\right]$

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David C. Lay, Steven R. Lay, Judi J. McDonald

Linear Algebra and Its Applications

Grace H.

Anna Marie V.

Heather Z.

Kayleah T.

Absolute Value - Example 1

Absolute Value - Example 2

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(b) $\left[\begin{array}{c}{6.36} \\ {8.14} \\ {11.73} \\ {4.78}\end{array}\right]$

Linear Algebra and Its Applications

Grace H.

Anna Marie V.

Heather Z.

Kayleah T.

Absolute Value - Example 1

Absolute Value - Example 2

David C. Lay, Steven R. Lay, Judi J. McDonaldLinear Algebra and Its Applications

Grace H.

Anna Marie V.

Heather Z.

Kayleah T.

David C. Lay, Steven R. Lay, Judi J. McDonald

Linear Algebra and Its Applications