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So in this video, we're going to talk about question 24 from chapter 20, which says right balanced equations describing the reaction of strontium with each of the following, o2s, cl2, p4, h2, h2o, and hcl.
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And i want to point out that all of this information is summarized in table 20 .7.
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So if you need a summary, you can look there.
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But we can also figure it out ourselves just by knowing that strontium likes to react to, lose two electrons to have its plus two charge to have the noble gas configuration, and then that ion is going to form ionic compounds.
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So when we have strontium plus o2, the ionic compound will be between strontium cat ions with a plus two charge and oxygen anions.
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Our oxygen usually takes a minus two charge.
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It likes to gain two electrons to reach the noble gas configuration.
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So we have plus 2 and minus 2.
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Our charges are balanced, but we need to balance the elements, the atoms, in our equation.
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So on the left -hand side, we have two oxygen atoms, and the right -hand side we have just one.
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So we need a coefficient of 2.
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So we have 2 -s -r -o, but now we have two strontium atoms on the right and just one on the left.
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So we also need a coefficient of 2 in front of our strontium.
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So the balanced chemical equation is 2 -s -r plus o2 yields 2 -sr.
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Next we have the reaction between strontium and sulfur, and this is actually really similar because oxygen and sulfur are from the same column or group of the periodic table.
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So we know that our strontium wants to form that plus two ions.
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We have strontium plus two and then sulfur also forms a minus two ion just like oxygen is so we have plus two and minus two our charges are balanced and our elements are actually balanced as well, so this equation is already balanced.
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We have s plus s yields sr.
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Next we have the reaction of strontium with chlorine with cl2.
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So again, our strontium is going to want to form that plus two ion.
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And then it's going to form an ionic compound with chloride ions.
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So the ion we form from chlorine is chloride with a minus one charge.
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It's one of our halides.
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So we have a minus one charge and a plus two charge.
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So we need two chlorides to balance that.
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So sr plus cl2 yields srcl2.
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Next we have strontium plus p4.
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So this time we're forming a slightly more complicated ionic compound.
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So we know that our strontium is going to have a plus two charge.
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And then we have phosphorus.
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What charge does phosphorus usually take? well, phosphorus likes to react to gain three electrons, to reach the noble gas configuration.
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So it's gonna have a minus three charge.
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So i have something with a plus two charge and something with a minus three charge.
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The least common multiple of two and three is six.
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So i'm gonna balance this as plus six and minus six.
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So my plus two, i need three of those to get to plus six.
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And my minus three, i need two of those to get to minus six.
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So plus six and minus six is balanced.
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So i have sr3, p2.
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And we clearly need to do some balancing in this equation.
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So on the left hand side, in our reactants, i have four phosphorus atoms.
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And on the right hand side, in our products, i have two phosphorus atoms.
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So i'm going to put a coefficient of two in front of our strontium phosphide, our product there...