Question
Write each rational expression in lowest terms.$$\frac{r^{2}-r-6}{r^{2}+r-12}$$
Step 1
The numerator $r^{2}-r-6$ can be factored into $(r-3)(r+2)$ and the denominator $r^{2}+r-12$ can be factored into $(r-3)(r+4)$. So, the rational expression becomes: $$\frac{r^{2}-r-6}{r^{2}+r-12} = \frac{(r-3)(r+2)}{(r-3)(r+4)}$$ Show more…
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