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So in this video, we're going to work through problem 44 from chapter 20, which asks us to write equations describing the reactions of 10, sn, with each of the following, cl2, o2, and hcl.
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So let's start with our reaction between 10 and chlorine, between sn and cl2.
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So in this case, our 10 is going to take an oxidation state of 4.
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And the chloride compound that we form is s -n -c -l -4.
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So in order to balance this equation, right now we have four chlorine atoms on the right -hand side, but only two chlorine atoms on the left.
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So we need a coefficient of two in front of our co2.
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And that makes our balanced chemical equation s -n plus 2 -cl2 forms s -n -c -l -4.
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Then we have our reaction between 10 and oxen.
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Between s -n and o2.
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So again, tin is going to take that same plus four oxidation state, but since our oxide ions take a charge of minus 2, we only need two of them...
