00:01
Okay, so we're asked to write equations for the following reactions with n -bermobutane, which is just burma -butane.
00:11
The n -betene, the n -betene, the n -bethron.
00:15
So the first one is with sodium hydroxide.
00:22
So we'll give this butanol.
00:29
So if we write it out, we have ch3, c -h -2.
01:01
Okay, so in the second one, we have n -bermabutane with ammonia, and this will give us an amine.
01:48
So notice we, we solved the same.
01:51
Amount of hydrogens on the left and the right with the amine.
01:54
So we have an amide with two hydrogens and then it's basically always conserved...