00:01
So we have to read equations for the substitution reaction with n -bermopetan, or just bromopensane, because the n just means normal, with sodium azide.
00:21
And we're going to get, the nitrogen is going to be the nucleophile, attacking the carbon, and expelling the leaving group.
00:30
So i have direct replacement, and this is the equation.
01:11
So for the next ones, i'm just going to replace what it's reacting with, and replacing the end of the product, because, the rest of it's still the same.
01:25
The next one is reacting with, so this is a, this is b, reacting with tromethylamine.
01:42
So again, same reaction, giving us this structure.
02:01
So that's going to be the same.
02:03
One difference is plus trimethylamine to give us, the next one is reacting with the acetylid ion to give us this product.
02:55
So we have the, we've been, we've nine carbon chain because we have five plus the four carbons.
02:59
Yeah, the alkyn is going to be the nucleophile, attacking the carbon, expeling the bermine.
03:05
So we have five, six, seven, eight, nine...