Now, we want to show that $\Phi((0,2)) > \Phi((1,3))$. By definition, we have:
$\Phi((0,2)) = \int_0^2 f(x) dx$ and $\Phi((1,3)) = \int_1^3 f(x) dx$.
To compare these two integrals, we can use the hint that $e^{-x^2/2}$ decreases as $|x|$ increases. This means
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