00:02
Let's predict the products of these reactions of alkynes.
00:07
Let's take the first one.
00:08
We have an internal alkyne and react it with cl2.
00:12
Well, we know that this has 1, 2, 3, 4 carbons, so we have one equivalent of co2, 1, 2, 3, 4.
00:21
Inside will be a double bond, and we'll have 2 chlorine atoms anti -additioned.
00:32
Here we have this molecule.
00:37
Of hbr, or this molecule, and we're reacting excess hbr.
00:42
Well, which of these atoms, a or b, would be the most stable carbon to have br attached to? well, it would be a.
01:00
So, and we're doing excess, which really only means two, in this case.
01:06
And, well, that is our product.
01:08
We have two atoms, one and two here.
01:10
An important part to know is that in an alkyne, even though it's drawn in a straight line, there are two carbons involved in the alkyne itself.
01:19
And it ends up making this linear structure.
01:21
The clearest example of this is butyne or two butyne...