00:01
In this question, it is about content scattering.
00:05
So the x -ray is shining on aluminum foil, and we found the, we are given the original frequency of the x -ray is 1 .21 times 10 to the 18 hertz.
00:22
The frequency of the scattered photon is 1 .203 times 10 to the 18 hertz.
00:30
So we want to find a scattering angle and the recalling speed of the electron.
00:36
So to do this problem, for the part a, we'll be writing down the compton scattering equation first.
00:55
It says that delta lambda equals to lambda minus lambda 0 equals to lambda c times 1 minus cosine data.
01:04
So first we find delta lambda, okay, because to lambda minus lambda not.
01:11
This is c over c over f minus c over f not.
01:23
Okay, so i'm going to substitute the values.
01:30
Okay, see that the frequency is 10 to the 18, so i'm going to pull that out.
01:40
1 over 1 .203 minus 1 over 1 .211.
01:48
You calculate this and you get 1 .44 times 10 to the negative 12 meters.
01:56
Then you can use this to calculate the sketching angle.
02:03
So 1 minus cosine theta equals to delta lambda over lambda c, 1 .44 times 10 to the negative...