00:01
Now we do one problem 137.
00:02
In problem 137, they give us this information.
00:08
They give us the formula of the compound, and in there, m is a known metal.
00:15
And then they heat this compound.
00:18
And after it hit compound, the water evaporate, and we have unhyrus solid solid.
00:26
And now, we know another information.
00:29
The beginning we have 0 .6 to 40 grams.
00:35
After we hit, we get the solid, that the mass equal 0 .5471 grams.
00:44
So how many grams of water evaporates? can we do this? we can do this because we're based on the lot of mass of conversion.
00:52
So we can find the mass of water equal.
00:55
Mass of the solid is initial, subject the mass of the hydrant.
01:00
So we had a mass of water.
01:03
And after we find the mass of water, we should find the mass, the more of water, right? because we saw the problem based on so chrometry.
01:13
Now we get the more of water...