00:01
Okay, this looks like sort of a different problem.
00:04
We're asked to calculate the entropy change for the surroundings when we have one liter of water, hot water, at 90 degrees celsius that is sitting in a 25 degree room.
00:16
The water cools to, i'm sure that should say 25 degrees celsius while the temperature of the room remains unchanged.
00:26
Changed.
00:32
So i have one liter of water will equal 1 ,000 grams of water, and i'm pretty sure i'm going to have to get that to moles eventually here, times 18 .00 grams per mole.
00:59
And let's see, 1 ,000 divided by 18 .02, 18 .02 equals 55 .49494 in case i need that.
01:24
So we are going to figure out that our delta h will be equal to our moles of water, our specific heat of water, times our moles of water, times our delta t of water, this will equal 75 .4 joules per k mole times 55 .494 moles times, since this is in k, i'm going to go ahead.
02:36
I don't really need to do this.
02:44
Let's go.
02:46
273 will equal 363 and 25 is 298.
02:58
So i will have 363 kelvin minus 298 kelvin...