00:01
For this problem, we'll go ahead and solve for the concentration of ammonia by simply using the titration data.
00:10
36 .78 mil liters or 0 .3678 liters of hcl are required to reach the equivalence point.
00:19
If we multiply the volume by the concentration, we'll get the moles of hcl that was used in the titration.
00:25
Because the reaction is one -to -one, it's also equal to the moles of ammonia.
00:29
Now that we have the moles of ammonia, we simply divide it.
00:32
It by the volume of the original ammonia solution, which was 25 milliliters, or 0 .025 liters.
00:39
We get a concentration of 0 .014545.
00:43
Then the ammonium concentration at the equivalence point is going to be equal to the moles of ammonium that are present, which will be equal to the moles of hcl that was added.
00:55
So we'll take our volume of hcl, 36 .78 milliliters...