Solve the equation in radians for all exact solutions where appropriate. Round approximate answers in radians to four decimal places. Write answers using the least possible nonnegative angle measures.
$$\sqrt{2} \sin 2x - 1 = 0$$
Choose the correct answer below.
A. The solution set is $$\left\{\frac{\pi}{2} + 2n\pi, \frac{3\pi}{2} + 2n\pi\text{, where n is any integer}\right\}$$
B. The solution set is $$\left\{\frac{\pi}{8} + 2n\pi, \frac{3\pi}{8} + 2n\pi\text{, where n is any integer}\right\}$$
C. The solution set is $$\left\{\frac{\pi}{8} + n\pi, \frac{3\pi}{8} + n\pi\text{, where n is any integer}\right\}$$
D. The solution set is $$\left\{\frac{\pi}{4} + 2n\pi, \frac{3\pi}{4} + 2n\pi\text{, where n is any integer}\right\}$$
