What is the major organic product of the following reaction? (Hint: enolates prefer conjugate attack if possible.)
+ CH3CH2COCH3 CH3O
0
I.
0
-CHCOCH3
0
0
O=C-CH3
0
IV.
CHCOCH3
O=C-CH3
II.
0
-CHCOCH3
0
HO-CH-CH3
V.
00
CH2CCH3
0
OH
CHCOCH3
III.
0=C-CH3
ENOLATE mechanism.
First step is base absorbs proton. and then 1, 4 addition.
H
H
CH
oc
CH
Answer:
CH3O
45
H+
CH
01-
CH
CH
CH
0
7
Why does it not like this below
in the green box of the answer?